Correct option is (A) 5√2

Let ABCD is a square of side 10 cm are lying inside the circle of radius r.
\(\because\angle ABC=90^\circ\) \((\because\) Angle in a square)
\(\therefore\) AC is a diameter \((\because\) Angle in a semicircle is \(90^\circ)\)
\(\therefore AC=\sqrt{AB^2+BC^2}=\sqrt{10^2+10^2}\)
\(=\sqrt{100+100}=10\sqrt2\,cm\)
\(\therefore\) Radius \(=\frac{Diameter}2\)
\(=\frac{AC}2=\frac{10\sqrt2}2=5\sqrt2\,cm\)