Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
121 views
in Mathematics by (15 points)
edited by
How many (i) straight line (ii) traingle can be formed by 13 points, 6 of which are in straight line...

Please log in or register to answer this question.

1 Answer

+1 vote
by (1.4k points)

∵ Straight line can be formed by joining two points & triangle can be formed by joining three non-collinear points.

(i) Number of ways in which 2 points are selected from 13 points = \(^{13}C_2\).

But given that 6 points are collinear (in straight line).

Therefore these 6 points can form only one line.

So, we have to subtract (\(^6C_2\) - 1) from the ways of selection 2 points from 13 points.

∴ Total straight lines that can be possible 

\(^{13}C_2\) - (\(^6C_2\) - 1)

\(\frac{13\times 12}{2}\) - \(\frac{6\times 5}{2}\) + 1

= 13 x 6 - 15 + 1

= 78 - 14

= 64.

(ii) Number of ways in which 3 non-collinear points are selected from 13 points = \(^{13}C_3\).

But given that 6 points are collinear that never be formed any triangle.

So, we have to subtract the selection of 3 non-collinear points from these 6 points.

So, total number of triangle = \(^{13}C_3\) - \(^{6}C_3\)

\(\frac{13\times 12\times 11}{3\times 2}\) - \(\frac{6\times 5\times 4}{3\times 2}\)

= 286 - 20

= 266.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...