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Find the value of

(i) ω18 

(ii) ω21

(iii) ω-30

(iv) ω-105 

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Best answer

ω3 = 1

(i) ω18 = (ω3)6 = (1)6 = 1

(ii) ω21 = (ω3)7 = (1)6 = 1

(iii) ω-30 = (ω3)-10 = (1)-10 = \(\frac{1}{(1)^{10}}\) = 1

(iv) ω-105 = (ω3)-35 = (1)-35 = \(\frac1{(1)^{35}}\) = 1

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