Question

If the concentration of OH^- ions in the reaction

Fe(OH)_3(s) ⇋ Fe³⁺_(aq) + 3OH^-_(aq) 

is decreased by 1/4 times, then concentration of Fe³⁺ will increase by equilibrium 

(a) 64 times

(b) 4 times

(c) 8 times

(d) 16 times

Answer 1

The correct option is : (a) 64 times

Explanation:

K = [Fe³⁺][OH^-]³ (activity of solid is taken unity) Concentration of OH^- ion in the reaction is decreased by 1/4 times then equilibrium concentration of Fe³⁺ will be increased by 64 times in order to keep the value of K constant.