Question

On the basis of the following E° values, the strongest oxidizing agent is

[Fe(CN)₆]^4- → [Fe(CN)₆]^3- + e^-; E° = -0.35 V

Fe²⁺ → Fe³⁺ + e^-; E° = -0.77 V

(a) Fe³⁺

(b) [Fe(CN)₆]^3-

(c) [Fe(CN)₆]^4-

(d) Fe²⁺

Answer 1

Correct option (a) Fe³⁺

Explanation :

[Fe(CN)₆]^4- → [Fe(CN)₆]^3- + e^-; E° = +0.35 V

Fe²⁺ → Fe³⁺ + e^-; E° = +0.77 V

Higher the +ve reduction potential, stronger will be the oxidising agent. Oxidising agent oxidises other compounds and gets itself reduced easily.