Given: 45.4 volume H2O2 solution
To find: % (by mass) of H2O2
Formula: Percentage (%) by mass = \(\frac{mass\,of\,solute}{mass\,of\,solutiuon}\) x 100
calculation: 45.4 volume H2O2 solution means 1 L of this solution will liberate 45.4 L of O2 at STP.
Hydrogen peroxide (H2O2 ) decomposes as:

% (by mass) of H2O2 in 45.4 volume H2O2 solution is 13.6%.