Given,
E0 = 120N/C, Let frequency V = 50. 0 MHZ
B0 = \(\frac{E_0}{c}\)
B0 = \(\frac{120}{3\times10^8}\)
B0 = 40 x 10-8
B0 = 400 x 10-9 T
ω = \(2\pi v\)
ω = 2\(\pi\) x 50 x 106
ω = 3.14 x 108 rad/5
\(K=\frac{w}{c}\)
\(K = \frac{3.14\times10^8}{3\times10^8}\)
K = 1.04 rad/m
Suppose electromagnetic wave is moving x direction, electric field be along y - direction and magnetic field alomg the z direction then,
E = E0 sin (kx - ωt) \(\hat{j}\)
E = 120 sin (1.04 x - 3.14 x 108 t) \(\hat{j}\)
and,
B = B0 sin (kx - ωt) \(\hat{k}\)
B = 400 x 10-9 sin (1.05 x - 3.14 x 108 + t) \(\hat{k}\)