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The solubility of AgCl wili be minimum in

(a) 0.01 M CaCl2 

(b) Pure water

(c) 0.001 M AgNO3 

(d) 0.01 M NaCl

1 Answer

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Best answer

The correct option is : (a) 0.01 M CaCl2 

Explanation:

There are greater number of particles (i.e. ions) compared to others. Hence, solubility will be minimum.

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