Question

In acidic medium, H₂O₂ changes Cr₂O₇^2- to CrO₅ which has two (-O - O -) bonds. Oxidation state of Cr in CrO₅ is

(a) +5 

(b) +3 

(c) +6 

(d) -10

Answer 1

The correct option is : (c) +6 

Explanation:

CrO₅ has butterfly structure having two peroxo bonds.

Peroxo oxygen has -1 oxidation state.

Let oxidation state of Cr be 'x'

CrO₅ : x + 4(-1) + 1 (-2) = 0 => x = + 6