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+1 vote
40.6k views
in d-and f-Block Elements by (45.3k points)
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KMnO4 reacts with oxalic acid according to the equation

2Mn4- + 5C2O42- + 16H+ → 2Mn2+ +10CO2 + 8H2O

Here 20 mL of 0.1 M KMnO4 is equivalent to

(a) 50 mL of 0.5 M C2H2O4

(b) 20 mL of 0.1 M C2H2O4

(c) 20 mL of 0.5 M C2H2O4

(d) 50 mL of 0.1 M C2H2O4

1 Answer

+2 votes
by (67.9k points)
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Best answer

Correct option (d) 50 mL of 0.1 M C2H2O4

Explanation :

Therefore, these are equivalent.

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