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The nuclei 6C13 and 7N14 can be described as 

(a) isotones 

(b) isobars 

(c) isotopes of carbon 

(d) isotopes of nitrogen

1 Answer

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Best answer

The correct option is (a) isotones.

Explanation:

As 6C13 and 7N14 have same no. of neutrons (13-6=7 for C and 14-7=7 for N), they are isotones.

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