Question

Calculate the temperature of 5.0 mol of a gas occupying 5 dm³ at 3.32 bar. 

(R = 0.083 bar dm³ K^-1 mol^-1)

Answer 1

Given: n = number of moles = 5.0 mol, V = volume = 5 dm³

P = pressure = 3.32 bar, R = 0.083 bar dm³ K^-1 mol^-1

To find: Temperature (T) 

Formula: PV = nRT

Calculation: According to ideal gas equation, 

PV = nRT

∴ T = \(\frac{PV}{nR}\) = \(\frac{3.32\times 5}{5.0\times0.083}\) = 40 K

The temperature of the gas is 40 K.