Correct option is: (C) 112 g mol-1
PV = nRT = PV = \(\frac WM RT\)
= PM = \(\frac WV RT\)
= PM = \(\rho\)RT ....(i)
Let say density of \(N_2\) at 4 bat = \(\rho\)
then the density of unknown gas at 2 atm = 2\(\rho\)
Using equation (i)
For \(N_2\) gas
4 \(\times\) 28 = \(\rho\) \(\times\) R \(\times\) 300 ...(ii)
for unknown gas
2 \(\times\) M = 2e \(\times\) R \(\times\) 300 ....(iii)
iii ÷ ii, we got
\(\frac {2M}{4\times28} = \frac {2\rho\times R\times300}{\rho\times r\times 300}\)
M = \(\frac {2 \times 4\times 28}{2}\)
M = 112 g/mol