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At 300 K, the density of a certain gaseous molecule at 2 bar is double to that of dinitrogen at 4 bar. The molar mass of gaseous molecule is ……………. 

(A) 28 g mol-1

(B) 56 g mol-1 

(C) 112 g mol-1

(D) 224 g mol-1

2 Answers

+1 vote
by (66.4k points)
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Best answer

Correct option is: (C) 112 g mol-1

PV = nRT = PV = \(\frac WM RT\)

= PM = \(\frac WV RT\) 

= PM = \(\rho\)RT ....(i)

Let say density of \(N_2\) at 4 bat = \(\rho\)

then the density of unknown gas at 2 atm = 2\(\rho\)

Using equation (i) 

For \(N_2\) gas 

\(\times\) 28 = \(\rho\) \(\times\) R \(\times\) 300 ...(ii)

for unknown gas 

2 \(\times\) M = 2e \(\times\) R \(\times\) 300 ....(iii)

iii ÷ ii, we got

\(\frac {2M}{4\times28} = \frac {2\rho\times R\times300}{\rho\times r\times 300}\)

M = \(\frac {2 \times 4\times 28}{2}\) 

M = 112 g/mol

+1 vote
by (32.5k points)

(C) 112 g mol-1

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