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+1 vote
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The ratio of escape velocity at earth (ve) to the escape velocity at a planet  (vp)  whose radius and  mean density are twice as that of earth is

(a) 1:4

(b) 1 : 2

(c) 1:2

(d) 1: 2√2

1 Answer

+3 votes
by (76.4k points)
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Best answer

Correct option (d) 1: 2√2

Explanation:

 As escape velocity,

v = √(2GM/R)

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