Question

Displacement between maximum potential energy position and maximum kinetic energy position for a particle executing simple harmonic motion is

(a) ± a/2

(b) + a

(c) ± a

(d) -1.

Answer 1

Option (c) is correct

Fora SHM the PE of the particle is zero at equilibrium position where KE is maximum.

Again at the extreme positions for displacement =+a or -a ,the KE of the particle is zero it has got maximum PE.

Hence displacement between these two points is +a or -a , where a is the amplitude of the SHM.

Answer 2

Correct option  (c) ± a

Explanation:

For a simple harmonic motion between A and B with O as the mean position, maximum kinetic energy of the particle executing SHM will be at O and maximum potential energy will be at A and B.

Displacement between maximum potential energy and maximum kinetic energy is ± a.