Consider two rods of same length and different specific heats (S1, S2), conductivities (K1 K2) and area of cross-sections (A1 A2)) and both having temperatures T1. and T2 at their ends. If rate of loss of heat due to conduction is equal. then
(a) K1A1 = K2A2
(b) K1A1/S1 = K2A2/S2
(c) K2A1 = K1A2
(d) K2A1/S2 = K1A1/S1
