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Find the number of permutations of letters in each of the following words.

(i) DIVYA

(ii) SHANTARAM

(iii) REPRESENT

(iv) COMBINE

(v) BAL BHARATI

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(i) There are 5 distinct letters in the word DIVYA.

∴ Number of permutations of the letters of the word DIVYA = 5! = 120

(ii) There are 9 letters in the word SHANTARAM in which ‘A’ is repeated 3 times.

∴ Number of permutations of the letters of the word SHANTARAM = \(\frac{9!}{3!}\)

 = 9 x 8 x 7 x 6 x 5 x 4

 = 60480

(iii) There are 9 letters in the word REPRESENT in which ‘E’ is repeated 3 times and ‘R’ is repeated 2 times.

∴ Number of permutations of the letters of the word REPRESENT = \(\frac{9!}{3!2!}\) 

 = \(\frac{9\times8\times7\times6\times5\times4}2\) = 30240

(iv) There are 7 distinct letters in the word COMBINE.

∴ Number of permutations of the letters of the word COMBINE = 7! = 5040

(v) There are 10 letters in the word BALBHARATI in which ‘B’ is repeated 2 times and ‘A’ is repeated 3 times.

∴ Number of permutations of the letters of the word BALBHARATI = \(\frac{10!}{2!3!}\)

\(=\frac{10\times9\times8\times7\times6\times5\times4\times3\times2\times1}{2\times3\times2}\) 

 = 302400

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