Question

The gauge pressure 1 mm below the water surface open to atmosphere is [ Density of water = 10² kg/m³, atmospheric pressure = 101.3 kPa] (a) 101310 Pa (b) 101290 Pa (10 Pa (d) 1-0 Pa

Answer 1

Correct option is: (A) 101310 Pa

Given P₀ = 101.3 kPa

\(\rho\) = 10² kg/m³

h = 1 x 10^-3 m

Pressure

P = P₀ + \(\rho\)gh

P = 101.3 x 10³ + 10² x 10 x 1 x 10^-3

P = 101300 + 1

P = 101301 Pa