Question

Prove the following:  

tan (π/4+θ) = 1+tanθ/1-tanθ

Answer 1

L.H.S = tan(π/4+θ)

= \(\frac{tan\frac{\pi}{4}+tan \theta}{1-tan\frac{\pi}{4}tan\theta}\)

= \(\frac{1+tan\theta}{1-(1)tan\theta}\)

=\(\frac{1+tan\theta}{1-tan\theta}\)

=RHS