Question

The frequency of revolution of a particle performing circular motion changes from 60 rpm to 180 rpm in 20 seconds. Calculate the angular acceleration of the particle.

Answer 1

Data : f₁ = 60 rpm = \(\frac{60}{60}\) rev/s = 1 

rev/s, f₂ = 180 rpm = \(\frac{180}{60}\) rev/s = 3 

rev/s, t = 20 s

The angular acceleration in SI units,

OR 

Using non SI units, the angular frequencies are ω₁ = 60 rpm = 1 rps and ω₂ = 180 rpm = 3 rps.