(1 - x2) (x + 2/x)6 = (x + 2/x)6 - x2(x + 2/x)6
Consider (x + 2/x)6
Here, a = x, b = 2/x, n = 6
We have

To get the term independent of x in the expansion of (x + 2/x)6, we must have

To get the term independent of x in the expansion of x2(x + 2/x)6, we must have

\(\therefore\) Term independent of x in the expansion of
