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Find the term independent of x in the expansion of (1 - x2)(x + 2/x)6

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(1 - x2) (x + 2/x)6 = (x + 2/x)6 - x2(x + 2/x)6

Consider (x + 2/x)6

Here, a = x, b = 2/x, n = 6

We have

To get the term independent of x in the expansion of (x + 2/x)6, we must have

To get the term independent of x in the expansion of x2(x + 2/x)6, we must have

\(\therefore\) Term independent of x in the expansion of

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