Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
2.9k views
in Physics by (32.5k points)
closed by

The moment of inertia of a disc about an axis through its centre and perpendicular to its plane is 10 kg.m2 . Find its MI about a diameter.

1 Answer

+1 vote
by (32.6k points)
selected by
 
Best answer

Data : Iz = 10 kg.m2

If the disc lies in the xy plane with its centre at the origin then, according to the theorem of perpendicular axes,

Ix + Iy = Iz

Since, Ix = Iy , 2Ix = Iz

∴ Its MI about a diameter,

Ix\(\frac{I_z}2\) = \(\frac{10}2\)= 5 kg.m2

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...