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If `x= 2 sintheta - sin2theta` and `y= 2 costheta - cos 2theta ` then `(d^2y)/(dx^2) " at " theta =pi ` is :

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If `x= 2 sintheta - sin2theta` and `y= 2 costheta - cos 2theta ` then `(d^2y)/(dx^2) " at " theta =pi ` is :
A. `-3/8`
B. `3/2`
C. `-3/4`
D. `3/4`
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Correct Answer - A
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