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A solid sphere, starting from rest, rolls down two different inclined planes from the same height but with different angles of inclination θ1 > θ2 . On which plane will the sphere take longer time to roll down?

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Let L1 and L2 be the distances rolled down by the sphere along the corresponding inclines from the same height h. 

∴ L1 sin θ1 = L2 sin θ2 = h

Therefore,  h being the same, \(V_{CM1}\) = \(V_{CM2}\)

v = u + at

with u = 0 and  \(V_{CM1}\) = \(V_{CM2}\), aCM1t1 = aCM2t2.

The sphere will take longer time to roll down from the same height on the plane with smaller inclination.

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