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If kx + 2y – 1 = 0 and 6x – 4y + 2 = 0 are identical lines, then determine k. 

(a) -3 

(b) - 1/3

(c) 1/3

(d) 3  

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Best answer

Correct option is (a) -3

Lines kx + 2y – 1 = 0 and 6x – 4y + 2 = 0 are identical.

∴ k/6 = 2/-4 = -1/2

∴ k = -3

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