Given, slope = 4, x-intercept = 5
Since the x-intercept of the line is 5, it passes through (5, 0).
Equation of the line in slope point form is y – y = m(x – x )
Equation of the required line is
y – 0 = 4(x – 5)
y = 4x – 20
4x – y = 20
4x/20 - y/20 = 1
x/5 + y/(-20) = 1
This equation is of the form x/a + y/b = 1
where x-intercept = b, y-intercept = -20