Data : λ = 5000 Å = 5000 × 10-10 m
= 5 × 10-7 m, v = 500 m/s
(i) speed (v) = \(\frac{distance(\lambda)}{time(T)}\)
∴ The time interval between successive collisions of a gas molecule, T = \(\frac{\lambda}v\)
= \(\frac{5\times10^{-7}m}{500\,m/s}\) = 10-9 s
(ii) The collision frequency (number of collisions per unit time) of a gas molecule, f = \(\frac1T\) = \(\frac1{10^{-9}\,s}\) = 109 collisions per second
