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in Coordinate Geometry by (42.5k points)
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Eccentricity of the hyperbola 16x2 – 3y2 – 32x – 12y – 44 = 0 is

(A) \(\sqrt{\frac {17}{3}}\)

(B) \(\sqrt{\frac {19}{3}}\)

(C) \(\frac {\sqrt19}{3}\)

(D)\(\frac {\sqrt17}{3}\)

1 Answer

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Best answer

Correct option is: (B) \(\sqrt{\frac {19}{3}}\)

16x2 – 3y2 – 32x – 12y – 44 = 0 

⇒ 16(x – 1)2 – 3(y + 2)2 = 48

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