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Find the equation of the hyperbola in the standard form if: Length of conjugate axis is 5 and distance between foci is 13.

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Let the required equation of hyperbola be \(\frac {x^2}{a^2} - \frac {y^2}{b^2} = 1\)

Length of conjugate axis = 2b 

Given, length of conjugate axis = 5 

2b = 5

b = 5/2

b2 = 25/4

Distance between foci = 2ae 

Given, distance between foci = 13 

2ae = 13

ae = 13/2

a2 e2 = 169/4

Now, b2 = a2 (e2 – 1)

b2 = a2 e2 – a2

25/4 = 169/4 - a2

a2 = 169/4 - 25/4 = 36

∴ The required equation of hyperbola is \(\frac {x^2}{36} - \frac {y^2}{\frac {25}{4}} = 1\)

i.e., \(\frac {x^2}{36} - \frac {4y^2}{25} = 1\)

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