Data : QH = 6 × 104 J, TH = 600K, TC = 500K
(i) The heat rejected by the engine

(ii) The work done by the engine, W = QH + QC = 6 x 104 J + (-5 x 104 J) = 1 x 104 J
(iii) The efficiency of the engine = \(\frac{W}{Q_H}\) = \(\frac{1\times10^4 J}{6\times10^4J}\) = \(\frac16\) > 16.67 %