Question

The ionic product of water at 25°C is 10^-14. Its ionic product at 90°C will be

(a) 1 x 16^-14

(b) 1 x 10^-12

(c) 1 x 10^-20

(d) 1 x 19^-16

Answer 1

Correct option  (a) 1 x 16^-14

Explanation:

The product of H⁺ and OH^- ions in water at a particular temperature is known as ionic product of water. It is denoted as K_w.

K_w = [H⁺][OH^-]

The value of K_w increase with the increase of temperature i.e. concentration of H⁺ and OH^- ions increase with increase of temperature, but it still exists in the range of 10^-14