Question

Calculate the time taken by a body performing SHM of period 2 seconds to cover half the amplitude starting from an extreme position.

Answer 1

Data : T = 2 s, x₀ = + A (initially at positive extremity), x = \(\frac A2\)

\(\omega\) = \(\frac{2\pi}T\) = \(\frac{2\pi}2\) = \(\pi\) rad/s

Assuming the particle starts from positive extremity,

x = A cos \(\omega\)t

∴ Starting from the positive extremity, the particle takes \(\frac 13\)s to cover a distance equal to half the amplitude.