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If log3 [log2 (log3 x)] = 1, show that x = 6561.

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If log3 [log2 (log3 x)] = 1, show that x = 6561.

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log3 [log2 (log3 x)] = 1 

∴ log2 (log3 x) = 31 

∴ log3 x = 23 

∴ log3 x = 8 

∴ x = 38 

∴ x = 6561

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If log3 [log2 (log3 x)] = 1, show that x = 6561.
asked Aug 30, 2021 in Mathematics by Adarsh01 (33.6k points)

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