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A position dependent force, F = 7-2x+3x^2-N acts on a small body of mass 2kg and displaces it from x = 0 to x = 5m. The work done in joules is ___________

(a) 135

(b) 270

(c) 35

(d) 70

1 Answer

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Best answer
Right option is (a) 135

Easy explanation: W = ∫Fdx = (int_0^5 (7-2x+3x^2)dx = [7x-x^2+x^3]_0^5)

W = 35-25+125=135J.

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