Correct answer is (c) 100°
The best explanation: Heat required to change 1g of ice at 0°C first into the water at 0°C and then into the water at 100°C,
Q=mL+mc∆T=1×80+1×1×100=180cal
Now 1g of steam carries 540cal of heat when 1g of steam is mixed with 1g of ice, entire steam will not condense. Finally, we will have a mixture of water and steam at 100°C.
