Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
125 views
in Physics by (121k points)
closed by
A metal plate 5cm×5cm rest on a layer of castor oil 1mm thick whose coefficient of viscosity is 1.55Nsm^(-2). Find the horizontal force required to move the plate with a speed of 2 cms^(-1).

(a) 0.775N

(b) 0.0577N

(c) 0.0775N

(d) 0.577N

1 Answer

0 votes
by (121k points)
selected by
 
Best answer
The correct answer is (c) 0.0775N

For explanation: F=ȠA dv/dx

F=1.55×25×10^-4×(2×10^-2)/(1×10^-3)=0.0775N.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...