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Oxidation state of sulphur in S8, H2S and S2F2 is

(a) 0, -2, -1

(b) 0, +2, -1

(c) 1, -2, +1.

(d) 0, -2, +1

1 Answer

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Best answer

Correct option  (d) 0, -2, +1

Explanation:

Oxidation state of S in S8 = 0

Oxidation state of S in H2S ⇒ +2 + x = 0

⇒ x = -2

Oxidation state of S2F2 in ⇒ 2x + 2(-1)=0

⇒ x = +1

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