Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
1.0k views
in Physics by (121k points)
closed by
A thin converging lens and a thin diverging lens of each focal length 10 cm are placed coaxially 5cm apart. What will be the focal length of the combination?

(a) +10cm

(b) -10cm

(c) +20cm

(d) -20cm

1 Answer

0 votes
by (121k points)
selected by
 
Best answer
Right answer is (c) +20cm

Explanation: We know, f1=10 cm, f2 = -10 cm, d = 5 cm

(frac{1}{f}=frac{1}{f_1}+frac{1}{f_2}-frac{d}{f_1f_2})

= 1/10 – 1/10 + 5/100

f = + 20 cm.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...