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Show how you would connect three resistors, each of resistance 6Ω, so that the combination has a resistance of (i) 9Ω (ii) 4Ω.

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(i) In order to get a resistance of 9‎Ω, We connect the given resistors (each of resistance of 6‎Ω) in the following way. Resistance between B and C

Resistance of the combination = 6‎Ω + 3‎Ω = 9‎Ω

(ii) In order to get a resistance of 4‎Ω, we connect two resistors in series and third in parallel as shown in the figure.
Resistors AB and BC are in series, therefore.

Rs =6‎Ω+6‎Ω=12‎Ω

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