(i) In order to get a resistance of 9Ω, We connect the given resistors (each of resistance of 6Ω) in the following way. Resistance between B and C


Resistance of the combination = 6Ω + 3Ω = 9Ω
(ii) In order to get a resistance of 4Ω, we connect two resistors in series and third in parallel as shown in the figure.
Resistors AB and BC are in series, therefore.
Rs =6Ω+6Ω=12Ω

