An alkene on ozonolysis gives only one product `(Z)`. `Z` on reaction with Fehling solution give red precipitate of `Cu_(2)O`. A

An alkene on ozonolysis gives only one product `(Z)`. `Z` on reaction with Fehling solution give red precipitate of `Cu_(2)O`. Alkene will be?
A. `Ph-CH=CH-Ph`
B. `(CH_(3))_(2)C=C(CH_(3))_(2)`
C. `CH_(3)-CH=C(CH_(3))_(2)`
D. `CH_(3)-CH=CH-CH_(3)`

An alkene on ozonolysis gives only one product `(Z)`. `Z` on reaction with Fehling solution give red precipitate of `Cu_(2)O`. Alkene will be?

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