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A particle executing SHM along a st. line has a velocity of 4 ms–1, when at a distance of 3 m from its mean position and 3 ms–1, when at a distance of 4 m from it. Find the time it takes to travel 2.5 m from the positive extremity of its oscillation.

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When the particle is at a distance 2.5 m from the extreme position, then its distance from the mean position,

x = 5 – 2.5 = 2.5 m

Since, the time is to be noted from the extreme postion for SHM therefore, we shall use the relation

x = a cos ωt

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