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The diagram above shows an isolated, positive charge Q. Point (B) is twice as far away from Q as point A. The ratio of the electric field strength at point A to the electric field strength at point B is

(A) 8 to 1 

(B) 4 to 1 

(C) 2 to 1 

(D) 1 to 1 

(E) 1 to 2

1 Answer

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Best answer

The correct option is: (B) 4 to 1

Explanation:

E ∝ 1/r2 so if r × 2, E ÷ 4

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