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Vertex of the parabola 9 x^2 - 6 x + 36 y + 9 = 0 is

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Vertex of the parabola 9 x2 - 6 x + 36 y + 9 = 0 is

(a) (1 /3, - 2 / 9) 

(b) (-1 /3, - 1 / 2) 

(c) (-1 /3, 1 / 2) 

(d) (1 /3, 1 / 2)

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1 Answer

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Best answer

Correct option  (a) (1 /3, - 2 / 9) 

Explanation:

The equation can be written as (3x - 1)2 = -4(9y + 2) .

Hence the vertex is (1/3,-2/9).

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