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For the reaction -rA = (frac{1670[A][Po]}{6+CA} frac{kmol}{ml.hr}) write the units for constants 6 and 1670.

(a) kmol/ml and 1/hr

(b) 1/hr and 1/hr

(c) kmol and kmol

(d) data insufficient

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The correct option is (a) kmol/ml and 1/hr

The explanation: To get the final units

-rA = (frac{1670[frac{kmol}{ml}][frac{kmol}{ml}]}{6+frac{kmol}{ml}} )

The units of constants have to be 1/hr for 1670 and kmol/ml for 6.

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