Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
20.4k views
in Electrostatics by (80.9k points)
recategorized by

Sphere X of mass M and charge +q hangs from a string as shown above. Sphere Y has an equal charge +q and is fixed in place a distance d directly below sphere X. If sphere X is in equilibrium, the tension in the string is most nearly

(A) Mg 

(B) Mg + kq/d 

(C) Mg – kq/d 

(D) Mg + kq2/d2 

(E) Mg – kq2/d2

1 Answer

+1 vote
by (52.5k points)
selected by
 
Best answer

The correct option is: (E) Mg – kq2/d2

Explanation:

ΣF = 0 so we have T + k(q)(q)/d2 – Mg = 0 giving T = Mg – kq2/d2

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...