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If 28 grams of N2 and 10 grams of H2 are reacted, how much NH3 will produce?

(a) 17 grams

(b) 34 grams

(c) 51 grams

(d) 54 grams

1 Answer

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Correct choice is (b) 34 grams

Explanation: Moles of N2 = 28/28 = 1, moles of H2 = 10/2 = 5, Reaction is N2 + 3H2 -> 2NH3, => N2 is limiting reagent, => moles of NH3 = 2*1 = 2, => weight of NH3 = 2*17 = 34 grams.

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