Question

CH4 with pressure 10 atm and volume 5 liter at 27^oC is passed into a reactor with 50% excess oxygen, how many moles of oxygen is left in the products?

(a) 2

(b) 4

(c) 6

(d) 8

Answer 1

Correct answer is (a) 2

The best explanation: The reaction is CH4 + 2O2 -> CO2 + 2H2O, moles of CH4 = 10*5/(0.0821*300) = 2, => moles of O2 left = 2*2(50/100) = 2.