What is the enthalpy of reaction forC6H6 -> 3C2H2, if the conversion of C6H6 is 80%, and heat of formation of C6H6, and C2H2 are 24 J, and 8 J?

Question

What is the enthalpy of reaction forC6H6 -> 3C2H2, if the conversion of C6H6 is 80%, and heat of formation of C6H6, and C2H2 are 24 J, and 8 J?

(a) 0

(b) 2.4 J

(c) 4.8 J

(d) 5.6 J

Answer 1

The correct option is (c) 4.8 J

The best I can explain: Heat of reaction = 3*8*0.8 + 24*0.2 – 24*0.8 = 4.8 J.