Question

A charge is placed at the centre of cube of side a then flux linked with one of its given faces will be

(a) Q/ε₀

(b) Q/6ε₀

(c) Q/ε₀a²

(d) Q/4πε₀a²

Answer 1

Correct option (b) Q/6ε₀

Explanation:

Gauss's law tells that the total flux through an area enclosing a charge Q is Q/ε₀. Now as the cube is having six faces and as we can assume a symmetrical distribution of fluxes among its faces, the flux associated with one of it faces is Q/6ε₀.