The correct answer is (a) ln((frac{k_2}{k_1})) = –(frac{E}{R} (frac{1}{T_2} – frac{1}{T_1}) )
For explanation I would say: By Arrhenius equation, k = (Ae^{frac{-Ea}{RT}},) where A is the frequency factor.
For two different temperatures, T1 and T2, the Arrhenius equation is reduced as ln((frac{k_2}{k_1})) = –(frac{E}{R}(frac{1}{T_2} – frac{1}{T_1}). )